Numford
Unit conversion

Convert 1 dyne into newton using dimensional analysis

1 dyne = 10⁻⁵ newton. Force is [M L T⁻²], so only the powers of mass, length and time decide the factor.

1 dyne 10⁻⁵ newton

Working

Step by step

  1. The dimension of forceForce has the dimensions [M L T⁻²]. Only the powers of M, L and T matter for the conversion.
  2. The conversion ruleA quantity with dimensions [Ma Lb Tc] has the number n₂ = n₁ [M₁/M₂]ᵃ [L₁/L₂]ᵇ [T₁/T₂]ᶜ in the new system. Here n₂ = n₁ [M₁/M₂] [L₁/L₂] [T₁/T₂]⁻².
  3. The size of each base unitM: 1 gram (g) is 0.001 kilogram (kg). L: 1 centimetre (cm) is 0.01 metre (m). T: 1 second (s) is the same in both systems.
  4. Put the numbers inn₂ = 1 [1 g / 1 kg] [1 cm / 1 m] [1 s / 1 s]⁻²
  5. Work out each bracket[M₁/M₂] = 0.001; [L₁/L₂] = 0.01; [T₁/T₂]⁻² = 1⁻² = 1
  6. Multiplyn₂ = 1 × 0.001 × 0.01 × 1 = 10⁻⁵
  7. The answer1 dyne = 10⁻⁵ newton
Questions

Dyne to newton: quick answers

How do you convert dyne to newton?

Force is [M L T⁻²]. Multiply by the ratio of each base unit raised to its power in the dimension. That gives 1 dyne = 10⁻⁵ newton.

What is 1 dyne in newton?

1 dyne = 10⁻⁵ newton.

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