Balance Fe + CuSO₄ → FeSO₄ + Cu
Fe(s) + CuSO₄(aq) → FeSO₄(aq) + Cu(s)
Balance an equation
Fe(s)+CuSO₄(aq)→FeSO₄(aq)+Cu(s)
Balanced
Atoms on each side
| Atom | As writtenleft : right | Balancedleft : right |
|---|---|---|
| Fe | 1:1 | 1:1 |
| Cu | 1:1 | 1:1 |
| S | 1:1 | 1:1 |
| O | 4:4 | 4:4 |
Check atoms
How to balance it, step by step
- Count each element on both sides. Every count already matches, so no coefficients are needed.
- Check: Fe 1 = 1, Cu 1 = 1, S 1 = 1, O 4 = 4. Balanced.
What happens
It is a displacement reaction: a more reactive element pushes a less reactive one out of its compound. An iron nail in copper sulphate solution turns brownish as copper coats it, and the blue solution turns light green.
Iron and copper sulphate: quick answers
What is the balanced equation for iron and copper sulphate?
Fe(s) + CuSO₄(aq) → FeSO₄(aq) + Cu(s). It is already balanced as written, so every coefficient is 1. Each side then has 1 Fe, 1 Cu, 1 S and 4 O.
What type of reaction is iron and copper sulphate?
It is a displacement reaction: a more reactive element pushes a less reactive one out of its compound. An iron nail in copper sulphate solution turns brownish as copper coats it, and the blue solution turns light green.
How do you balance Fe + CuSO₄ → FeSO₄ + Cu?
Count the atoms of each element on both sides: 1 Fe, 1 Cu, 1 S and 4 O. They already match, so no coefficients are needed.