Numford
Physics

Error analysis

How far can the answer be off?

Error in a formula

Product, quotient, power. The percentage errors add. Each counts as many times as its power. Sum or difference. The absolute errors add. A percentage needs the value to become an absolute error. Both in one formula. Worked out with the values, as the sum of slope times error. This is the worst case. The answer is always the maximum error.
Try
m
v

Maximum error in K

5%

K = 25.0 ± 1.25%

  • m1%1%
  • v22 × 2%4%
  • Totaladd them5%

Product, quotient or power: the percentage errors add, each counted |power| times.

Repeated readings

Mean. The sum of the readings divided by how many there are. Absolute error of a reading. How far it is from the mean, without a sign. Mean absolute error. The average of those distances. Write the result as mean ± this. Percentage error. The mean absolute error divided by the mean, times 100.

Separate the readings with spaces or commas.

Result

2.62 ± 0.11s

Mean
2.62 s
Mean absolute error
0.11 s
Relative error
0.041
Percentage error
4%
Error of each reading
  • 2.630.01
  • 2.560.06
  • 2.420.20
  • 2.710.09
  • 2.800.18

Least count

Least count. The smallest value an instrument can read. It is the smallest error you can make in one reading. Least count = 1 main scale division / number of vernier divisions.
Least count

0.1mm

= 0.01 cm

1 division, split in 10

1 mm / 10 = 0.1 mm

Least count = 1 main scale division / number of vernier divisions.

Worked examples

Error in a formula

Instruments

Least count of

Same chapter
Questions students ask

Errors in measurement

How do I find the error in a formula?

For a product, quotient or power, add the percentage errors, each multiplied by its power. If Z = A³ B / C², then ΔZ/Z = 3 ΔA/A + ΔB/B + 2 ΔC/C. For a sum or difference add the absolute errors: ΔZ = ΔA + ΔB.

Why are errors added even when the quantities are subtracted or divided?

The error shown is the largest possible one. In the worst case each measurement is off in the direction that pushes the result the same way, so the errors pile up.

How do I find the error of repeated readings?

Take the mean of the readings. The absolute error of each reading is its distance from the mean. The mean absolute error is the average of those distances, and the result is written as mean ± mean absolute error. For 2.63, 2.56, 2.42, 2.71 and 2.80 s it is 2.62 ± 0.11 s, a percentage error of 4%.

What is the least count?

It is the smallest value an instrument can read. For a vernier callipers it is 1 main scale division divided by the number of vernier divisions. For a screw gauge it is the pitch divided by the number of circular scale divisions.

What are absolute, relative and percentage error?

Absolute error is the size of the error in the unit of the quantity. Relative error is the absolute error divided by the value. Percentage error is the relative error times 100.

Why does a formula with a sum inside need the values?

A percentage error says how big the error is compared with the value, and a sum mixes values together. To add the errors of a sum you need the actual values, as in the equivalent resistance of two resistors in parallel: 100 ± 3 ohm and 200 ± 4 ohm give 66.7 ± 1.8 ohm.