Hybridisation of BrF₅
Br is sp³d² hybridised (hybridization by the VSEPR count): 5 sigma bonds and 1 lone pair give a square pyramidal shape, bond angle about 85°.
Why this shape
- Br has 7 valence electrons. It uses five in five single bonds to F, so two are left as one lone pair.
- Steric number = five sigma bonds + one lone pair = 6, so Br is sp³d² hybridised.
- Six electron pairs point to the corners of an octahedron (octahedral electron geometry). With one lone pair in place of atoms, the atoms make a square pyramidal shape.
- The lone pair takes any one of the six equal positions, and the five bonds form a square pyramid.
- The lone pair below the square pushes the four bonds up, so the angle between the top bond and the square is about 85 degrees, a little less than 90.
- The bond dipoles do not cancel in the square pyramidal shape, so BrF₅ is polar.
Lewis structure
42 valence electronsFormal charges: none
Why this hybridisation and shape
- Br has 7 valence electrons. It uses five in five single bonds to F, so two are left as one lone pair.
- Steric number = five sigma bonds + one lone pair = 6, so Br is sp³d² hybridised.
- Six electron pairs point to the corners of an octahedron (octahedral electron geometry). With one lone pair in place of atoms, the atoms make a square pyramidal shape.
- The lone pair takes any one of the six equal positions, and the five bonds form a square pyramid.
- The lone pair below the square pushes the four bonds up, so the angle between the top bond and the square is about 85 degrees, a little less than 90.
- The bond dipoles do not cancel in the square pyramidal shape, so BrF₅ is polar.
Class 11, Chapter 4 Chemical Bonding and Molecular Structure.
Hybridisation of BrF5: quick answers
What is the hybridisation of BrF5?
Br has 7 valence electrons. It uses five in five single bonds to F, so two are left as one lone pair. Steric number = five sigma bonds + one lone pair = 6, so Br is sp³d² hybridised.
What is the shape of BrF5 and its bond angle?
Square pyramidal, with a bond angle of about 85 degrees. Six electron pairs point to the corners of an octahedron (octahedral electron geometry). With one lone pair in place of atoms, the atoms make a square pyramidal shape. The lone pair takes any one of the six equal positions, and the five bonds form a square pyramid. The lone pair below the square pushes the four bonds up, so the angle between the top bond and the square is about 85 degrees, a little less than 90.
Is BrF5 polar or non-polar?
Polar. The bond dipoles do not cancel in the square pyramidal shape, so BrF₅ is polar.