Hybridisation of F₂
Each F atom is sp³ hybridised (hybridization by the VSEPR count): 1 sigma bond and 3 lone pairs give a linear shape.
Why this shape
- Each F has 7 valence electrons. It uses one in one single bond to F, so six are left as three lone pairs.
- Steric number = one sigma bond + three lone pairs = 4, so each F is sp³ hybridised.
- Four electron pairs point to the corners of a tetrahedron (tetrahedral electron geometry). With only two atoms, the molecule itself is a straight line.
- Two atoms always lie on a straight line, so there is no bond angle.
- Both atoms are the same, so the bond is non-polar.
Lewis structure
14 valence electronsFormal charges: none
Molecular orbitals
18 electronsdiamagnetic
(Nb − Na) / 2 = (10 − 8) / 2
σ1s² σ*1s² σ2s² σ*2s² σ2pz² (π2px² = π2py²) (π*2px² = π*2py²)
Why this hybridisation and shape
- Each F has 7 valence electrons. It uses one in one single bond to F, so six are left as three lone pairs.
- Steric number = one sigma bond + three lone pairs = 4, so each F is sp³ hybridised.
- Four electron pairs point to the corners of a tetrahedron (tetrahedral electron geometry). With only two atoms, the molecule itself is a straight line.
- Two atoms always lie on a straight line, so there is no bond angle.
- Both atoms are the same, so the bond is non-polar.
Class 11, Chapter 4 Chemical Bonding and Molecular Structure.
Hybridisation of F2: quick answers
What is the hybridisation of F2?
Each F has 7 valence electrons. It uses one in one single bond to F, so six are left as three lone pairs. Steric number = one sigma bond + three lone pairs = 4, so each F is sp³ hybridised.
What is the shape of F2 and its bond angle?
Linear. Four electron pairs point to the corners of a tetrahedron (tetrahedral electron geometry). With only two atoms, the molecule itself is a straight line. Two atoms always lie on a straight line, so there is no bond angle.
Is F2 polar or non-polar?
Non-polar. Both atoms are the same, so the bond is non-polar.