Hybridisation of SiH₄
Si is sp³ hybridised (hybridization by the VSEPR count): 4 sigma bonds and no lone pairs give a tetrahedral shape, bond angle 109.5°.
Why this shape
- Si has 4 valence electrons. It uses four in four single bonds to H, so none are left over.
- Steric number = four sigma bonds + no lone pairs = 4, so Si is sp³ hybridised.
- Four electron pairs point to the corners of a tetrahedron (tetrahedral electron geometry). With no lone pairs the atoms take the same shape: tetrahedral.
- All the bond pairs repel each other equally, so the angle is the ideal 109.5°.
- The bond dipoles cancel in the symmetric tetrahedral shape, so SiH₄ is non-polar.
Lewis structure
8 valence electronsFormal charges: none
Why this hybridisation and shape
- Si has 4 valence electrons. It uses four in four single bonds to H, so none are left over.
- Steric number = four sigma bonds + no lone pairs = 4, so Si is sp³ hybridised.
- Four electron pairs point to the corners of a tetrahedron (tetrahedral electron geometry). With no lone pairs the atoms take the same shape: tetrahedral.
- All the bond pairs repel each other equally, so the angle is the ideal 109.5°.
- The bond dipoles cancel in the symmetric tetrahedral shape, so SiH₄ is non-polar.
Class 11, Chapter 4 Chemical Bonding and Molecular Structure.
Hybridisation of SiH4: quick answers
What is the hybridisation of SiH4?
Si has 4 valence electrons. It uses four in four single bonds to H, so none are left over. Steric number = four sigma bonds + no lone pairs = 4, so Si is sp³ hybridised.
What is the shape of SiH4 and its bond angle?
Tetrahedral, with a bond angle of 109.5 degrees. Four electron pairs point to the corners of a tetrahedron (tetrahedral electron geometry). With no lone pairs the atoms take the same shape: tetrahedral. All the bond pairs repel each other equally, so the angle is the ideal 109.5°.
Is SiH4 polar or non-polar?
Non-polar. The bond dipoles cancel in the symmetric tetrahedral shape, so SiH₄ is non-polar.