Lewis structure of HCl
8 valence electrons. One Cl-H single bond, with three lone pairs on Cl.
Lewis structure
8 valence electronsFormal charges: none
Why this shape
- Cl has 7 valence electrons. It uses one in one single bond to H, so six are left as three lone pairs.
- Steric number = one sigma bond + three lone pairs = 4, so Cl is sp³ hybridised.
- Four electron pairs point to the corners of a tetrahedron (tetrahedral electron geometry). With only two atoms, the molecule itself is a straight line.
- Two atoms always lie on a straight line, so there is no bond angle.
- The two atoms are different, so the bond is polar and so is HCl.
How to draw it
- Count the valence electrons: Cl 7 + H 1 = 8 valence electrons, 4 pairs.
- Put Cl in the middle and join it to the other atom with single bonds.
- Give each outer atom lone pairs until it has an octet (H needs only two electrons), then put any electrons left over on the central atom.
- Result: one Cl-H single bond, with three lone pairs on Cl.
- Formal charge = valence electrons − lone pair electrons − number of bonds. Here: none.
Class 11, Chapter 4 Chemical Bonding and Molecular Structure.
Lewis structure of HCl: quick answers
How many valence electrons are in HCl?
Cl 7 + H 1 = 8 valence electrons, 4 pairs.
What are the formal charges in the Lewis structure of HCl?
Every atom has a formal charge of zero.
How many lone pairs are in the Lewis structure of HCl?
3 in all, 3 of them on the central Cl.