Aniline to chlorobenzene
2 steps: diazotisation, then Sandmeyer reaction
AnilineC₆H₅NH₂Amine - Step 1
NaNO₂ + HCl
273 to 278 K
Benzene diazonium chlorideC₆H₅N₂⁺Cl⁻Diazonium salt - Step 2
Cu₂Cl₂, HCl
ChlorobenzeneC₆H₅ClHaloarene
Exam answer
- Step 1: Aniline to benzene diazonium chloride: NaNO₂ + HCl, 273 to 278 K.
- Step 2: Benzene diazonium chloride to chlorobenzene: Cu₂Cl₂, HCl.
Alternative routes (2)
- Aniline → Benzene diazonium chloride → Benzene → Chlorobenzene
- Aniline to benzene diazonium chloride: NaNO₂ + HCl, 273 to 278 K.
- Benzene diazonium chloride to benzene: H₃PO₂ + H₂O.
- Benzene to chlorobenzene: Cl₂, anhydrous FeCl₃.
- Aniline → Benzene diazonium chloride → Phenol → Benzene → Chlorobenzene
- Aniline to benzene diazonium chloride: NaNO₂ + HCl, 273 to 278 K.
- Benzene diazonium chloride to phenol: H₂O, warm.
- Phenol to benzene: Zn dust, heat.
- Benzene to chlorobenzene: Cl₂, anhydrous FeCl₃.
Reagent and reason, step by step
- Step 1: Aniline to benzene diazonium chloride: NaNO₂ + HCl, 273 to 278 K Diazotisation: keep at 273 to 278 K or the salt decomposes. The acid generates HNO₂ in situ.
- Step 2: Benzene diazonium chloride to chlorobenzene: Cu₂Cl₂, HCl Sandmeyer reaction: cuprous chloride with HCl replaces N₂⁺ by Cl.
Aniline to chlorobenzene: quick answers
How many steps does it take to convert aniline to chlorobenzene?
2 steps: Aniline, then benzene diazonium chloride, then chlorobenzene.
Which named reaction is used to convert aniline to chlorobenzene?
Diazotisation and Sandmeyer reaction. A primary aromatic amine reacts with nitrous acid (NaNO2 and HCl) at 273 to 278 K to give a diazonium salt.
What is the reagent for step 1 of aniline to chlorobenzene?
Aniline to benzene diazonium chloride: NaNO₂ + HCl, 273 to 278 K. Diazotisation: keep at 273 to 278 K or the salt decomposes. The acid generates HNO₂ in situ.