Numford
Oxidation number

I in H₄IO₆⁻

I is +7 in the H4IO6- ion.

Oxidation number

Type a formula or an ion: K2Cr2O7, Cr2O7 2-, MnO4-, NH4+ or K4[Fe(CN)6]. Put a known ion in brackets when two elements are unknown. Pick an element to solve for it.

I+7

  1. Hydrogen is +1 when bonded to non-metals.
  2. Oxygen is −2 in most compounds.
  3. The oxidation numbers add up to the charge, −1: 4(+1) + 6(−2) + x = −1.
  4. x = +7.
Rule steps

How to find it

  1. Hydrogen is +1 when bonded to non-metals.
  2. Oxygen is −2 in most compounds.
  3. The oxidation numbers add up to the charge, −1: 4(+1) + 6(−2) + x = −1.
  4. x = +7.
Every atom

All the oxidation numbers in H₄IO₆⁻

  • H +14 atoms, hydrogen
  • O −26 atoms, oxygen
  • I +71 atom, sum rule
Questions

I in H₄IO₆⁻: quick answers

What is the oxidation number of I in H₄IO₆⁻?

I in H₄IO₆⁻ (the H4IO6- ion) is +7.

How do you find the oxidation number of I in H₄IO₆⁻?

Hydrogen is +1 when bonded to non-metals. Oxygen is −2 in most compounds. The oxidation numbers add up to the charge, −1: 4(+1) + 6(−2) + x = −1. x = +7.

What are the oxidation numbers of the other atoms in H₄IO₆⁻?

H +1, O −2. Together with I at +7 they add up to the charge of the ion, −1.

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