Numford
Circuits

Heating effect of current

The heat produced in a resistor is H = I²Rt, Joule's law of heating. A 4 Ω resistor carrying 2 A for 5 s gives H = 2² × 4 × 5 = 80 J.

Ohm's law

V = IR at a fixed temperature. Pick what to find and type the other two. Add a time to get the heat, H = I²Rt, and the energy in kWh.

Voltage V8 V
Power16 W
Heat80 J
Energy2.22 × 10⁻⁵ kWh
  1. V = IR = 2 × 4 = 8 V
  2. Power: P = VI = 8 × 2 = 16 W. The same as I²R and V²/R.
  3. Heat in 5 s: H = I²Rt = 2² × 4 × 5 = 80 J
  4. In units of electrical energy: 80 J / (3.6 × 10⁶ J per kWh) = 2.22 × 10⁻⁵ kWh
Derivation

Why it works

  1. A charge Q moving through a potential difference V has work W = VQ done on it.
  2. In a time t a steady current I carries Q = It, so W = VIt.
  3. In a resistor all of this energy becomes heat: H = VIt.
  4. With V = IR this is H = I²Rt. The heat goes as the square of the current, and with the resistance and the time.
  5. It is put to use in the electric iron, toaster, heater, bulb filament and fuse.
Questions

Heating effect of current: quick answers

What is Joule's law of heating?

The heat produced in a resistor is proportional to the square of the current, to the resistance and to the time: H = I²Rt.

How does a fuse protect a circuit?

A fuse is a short wire with a low melting point in series with the circuit. Too large a current heats it until it melts and breaks the circuit.

Why is tungsten used for bulb filaments?

It has a very high melting point, about 3380 °C, so it can glow white hot without melting. The bulb is filled with an inert gas so it does not burn.

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