Numford
Circuits

Resistance in series and parallel

Reduce the parallel group first, then add in series: 4 Ω and 12 Ω in parallel make 3 Ω, plus 3 Ω in series gives 6 Ω, so a 12 V cell drives 2 A.

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Tap a resistor to choose it, then change its value or add another in series or in parallel with it. The glowing dots are the current: faster where more flows. Brighter resistors turn more power into heat.

Equivalent resistance6 Ωbetween A and B
Current2 Afrom the cell
Power24 WP = VI
RIVPower
R₁4 Ω1.5 A6 V9 W
R₂12 Ω0.5 A6 V3 W
R₃3 Ω2 A6 V12 W

Step by step

  1. R₁ and R₂ in parallel: R = R₁R₂ / (R₁ + R₂) = 4 × 12 / (4 + 12) = 3 Ω
  2. The groups are in series: Req = 3 + 3 = 6 Ω
  3. Current from the cell: I = V / Req = 12 / 6 = 2 A
  4. Across the parallel group V = IR = 2 × 3 = 6 V, the same for every branch. It splits R₁: 6 / 4 = 1.5 A, R₂: 6 / 12 = 0.5 A.
  5. Drops in series: R₃: 2 × 3 = 6 V.
  6. Power: P = EI = 12 × 2 = 24 W.

Derivation

Why it works

  1. Series: one path, so the same current flows through each and the voltages add. Rs = R₁ + R₂ + R₃.
  2. Parallel: the same voltage is across each and the currents add. 1/Rp = 1/R₁ + 1/R₂ + 1/R₃.
  3. In a mixed circuit, find a group that is purely in series or purely in parallel and replace it by its equivalent.
  4. Repeat until one resistor is left. That is the equivalent resistance.
  5. Then work back out: the total current, the voltage across each group, and the current in each branch.
Questions

Series and parallel: quick answers

How do you solve a series and parallel combination?

Replace the innermost group first. Here 4 Ω ∥ 12 Ω = 4 × 12 / 16 = 3 Ω, then 3 + 3 = 6 Ω. The 12 V cell drives 2 A, which splits 1.5 A and 0.5 A in the parallel pair.

What is the difference between series and parallel?

In series the current is the same and the voltages add; the total is bigger than any one. In parallel the voltage is the same and the currents add; the total is smaller than any one.

What is the ratio of series to parallel resistance for n equal resistors?

n equal resistors R give nR in series and R/n in parallel, so the ratio is n². Two equal resistors give a ratio of 4.

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