Numford
Ray diagrams

Ray diagram of a convex lens: all 6 cases

A convex lens forms a real, inverted image for every object position except between F₁ and O, where the image is virtual, erect and enlarged.

The ray diagram

Drag the object or type values. Signs follow the New Cartesian convention: distances are measured from the pole or optical centre, along the incident light is positive, against it negative, and heights above the axis are positive. So u is negative for a real object.

Image distance v+30 cmbehind the lens
Magnification m-2inverted, 2 times
Image height h′-4 cmobject +2 cm
Power P+10 Dconverging
NatureReal, inverted, enlargedObject between F₁ and 2F₁
Image positionBeyond 2F₂Enlarged

Convex lens of focal length +10 cm. An object +2 cm tall at u = -15 cm: the image is at v = +30 cm, real, inverted, enlarged.

Unit
cm
Show the working
  1. f = +10 cm, u = -15 cm (the object is in front, so u is negative), h = +2 cm.
  2. 1/v = 1/f + 1/u = 1/(+10) + 1/(-15) = 5/150 = 1/30
  3. v = +30 cm: positive, so the image is behind the lens and real.
  4. m = v/u = (+30)/(-15) = -2: negative, so inverted, and enlarged.
  5. h′ = m × h = -2 × +2 = -4 cm
  6. Power P = 1/f = 1/(+0.1 m) = +10 D
All the cases

6 positions of the object

NCERT table

Image formation by a convex lens

ObjectImageSizeNature
At infinityAt the focus F₂Highly diminished, point-sizedReal and inverted
Beyond 2F₁Between F₂ and 2F₂DiminishedReal and inverted
At 2F₁At 2F₂Same sizeReal and inverted
Between F₁ and 2F₁Beyond 2F₂EnlargedReal and inverted
At the focus F₁At infinityInfinitely large or highly enlargedReal and inverted
Between F₁ and the optical centre OOn the same side of the lens as the objectEnlargedVirtual and erect
How to draw it

The rays to use

  • A ray parallel to the principal axis passes through the focus F₂ on the other side after refraction.
  • A ray through the optical centre O goes straight on without bending.
  • A ray through the focus F₁ comes out parallel to the principal axis.
  • Where the refracted rays meet is the top of the image.
With numbers

Object between 2F₁ and F₁, f = 10 cm

  1. f = +10 cm, u = -15 cm (the object is in front, so u is negative), h = +2 cm.
  2. 1/v = 1/f + 1/u = 1/(+10) + 1/(-15) = 5/150 = 1/30
  3. v = +30 cm: positive, so the image is behind the lens and real.
  4. m = v/u = (+30)/(-15) = -2: negative, so inverted, and enlarged.
  5. h′ = m × h = -2 × +2 = -4 cm
  6. Power P = 1/f = 1/(+0.1 m) = +10 D
Questions

Quick answers

How many cases of image formation are there for a convex lens?

Six: the object at infinity, beyond 2F₁, at 2F₁, between F₁ and 2F₁, at F₁, and between F₁ and the optical centre O.

When does a convex lens act as a magnifying glass?

When the object is between F₁ and O. The image is then virtual, erect and enlarged, on the same side as the object.

When is the image the same size as the object?

When the object is at 2F₁. The image forms at 2F₂ on the other side, real and inverted.

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