Bond order of N₂⁺
Bond order 2.5, paramagnetic. 13 electrons: Nb = 9, Na = 4.
Molecular orbitals
13 electrons2.5bond order
paramagnetic
paramagnetic
(Nb − Na) / 2 = (9 − 4) / 2
The atom columns show neutral atoms; the ion has 1 fewer electron in the molecule.
σ1s² σ*1s² σ2s² σ*2s² (π2px² = π2py²) σ2pz¹
Bond order step by step
- N₂⁺ has 13 electrons: 7 from each N, minus one for the positive charge.
- Up to N₂ (and its ions), the π2p pair lies below σ2pz and fills first.
- Configuration: σ1s² σ*1s² σ2s² σ*2s² (π2px² = π2py²) σ2pz¹
- Bonding electrons Nb = 9, antibonding electrons Na = 4.
- Bond order = (Nb − Na) / 2 = (9 − 4) / 2 = 2.5.
- One electron is unpaired (in σ2pz), so N₂⁺ is paramagnetic.
Class 11, Chapter 4 Chemical Bonding and Molecular Structure.
Bond order of N2+: quick answers
What is the bond order of N2+?
2.5. Bond order = (Nb − Na) / 2 = (9 − 4) / 2 = 2.5. Bonding electrons Nb = 9, antibonding electrons Na = 4.
Is N2+ paramagnetic or diamagnetic?
Paramagnetic. One electron is unpaired (in σ2pz), so N₂⁺ is paramagnetic.
What is the molecular orbital configuration of N2+?
σ1s² σ*1s² σ2s² σ*2s² (π2px² = π2py²) σ2pz¹, with 13 electrons in all.