Bond order of NO⁺
Bond order 3, diamagnetic. 14 electrons: Nb = 10, Na = 4.
Molecular orbitals
14 electrons3bond order
diamagnetic
diamagnetic
(Nb − Na) / 2 = (10 − 4) / 2
The atom columns show neutral atoms; the ion has 1 fewer electron in the molecule.
σ1s² σ*1s² σ2s² σ*2s² (π2px² = π2py²) σ2pz²
Bond order step by step
- NO⁺ has 14 electrons: 7 from N and 8 from O, minus one for the positive charge.
- With 14 electrons or fewer, the π2p pair lies below σ2pz and fills first.
- Configuration: σ1s² σ*1s² σ2s² σ*2s² (π2px² = π2py²) σ2pz²
- Bonding electrons Nb = 10, antibonding electrons Na = 4.
- Bond order = (Nb − Na) / 2 = (10 − 4) / 2 = 3.
- Every electron is paired, so NO⁺ is diamagnetic.
Class 11, Chapter 4 Chemical Bonding and Molecular Structure.
Bond order of NO+: quick answers
What is the bond order of NO+?
3. Bond order = (Nb − Na) / 2 = (10 − 4) / 2 = 3. Bonding electrons Nb = 10, antibonding electrons Na = 4.
Is NO+ paramagnetic or diamagnetic?
Diamagnetic. Every electron is paired, so NO⁺ is diamagnetic.
What is the molecular orbital configuration of NO+?
σ1s² σ*1s² σ2s² σ*2s² (π2px² = π2py²) σ2pz², with 14 electrons in all.