Molecular orbital diagram of He₂
Bond order 0, diamagnetic. 4 electrons: Nb = 2, Na = 2.
Molecular orbitals
4 electrons0bond order
diamagnetic
diamagnetic
(Nb − Na) / 2 = (2 − 2) / 2
σ1s² σ*1s²
Filling the diagram
- He₂ has 4 electrons: 2 from each He.
- Configuration: σ1s² σ*1s²
- Bonding electrons Nb = 2, antibonding electrons Na = 2.
- Bond order = (Nb − Na) / 2 = (2 − 2) / 2 = 0.
- Every electron is paired, so He₂ is diamagnetic.
- A bond order of zero means there is no bond: He₂ is not a stable molecule.
Class 11, Chapter 4 Chemical Bonding and Molecular Structure.
MO diagram of He2: quick answers
What is the molecular orbital configuration of He2?
σ1s² σ*1s². Configuration: σ1s² σ*1s²
What is the bond order of He2 from its MO diagram?
0: Nb = 2 and Na = 2, so (2 - 2) / 2 = 0. It is diamagnetic.
Why is σ2pz above π2p in He2?
Up to N2 the 2s and 2p orbitals are close in energy and mix, which pushes σ2pz above the π2p pair.