Molecular orbital diagram of Li₂
Bond order 1, diamagnetic. 6 electrons: Nb = 4, Na = 2.
Molecular orbitals
6 electrons1bond order
diamagnetic
diamagnetic
(Nb − Na) / 2 = (4 − 2) / 2
σ1s² σ*1s² σ2s²
Filling the diagram
- Li₂ has 6 electrons: 3 from each Li.
- Up to N₂ (and its ions), the π2p pair lies below σ2pz and fills first.
- Configuration: σ1s² σ*1s² σ2s²
- Bonding electrons Nb = 4, antibonding electrons Na = 2.
- Bond order = (Nb − Na) / 2 = (4 − 2) / 2 = 1.
- Every electron is paired, so Li₂ is diamagnetic.
Class 11, Chapter 4 Chemical Bonding and Molecular Structure.
MO diagram of Li2: quick answers
What is the molecular orbital configuration of Li2?
σ1s² σ*1s² σ2s². Up to N₂ (and its ions), the π2p pair lies below σ2pz and fills first.
What is the bond order of Li2 from its MO diagram?
1: Nb = 4 and Na = 2, so (4 - 2) / 2 = 1. It is diamagnetic.
Why is σ2pz above π2p in Li2?
Up to N2 the 2s and 2p orbitals are close in energy and mix, which pushes σ2pz above the π2p pair.