Benzene to iodobenzene
4 steps: substitution, then reduction, then diazotisation, then substitution
BenzeneC₆H₆Arene - Step 1
conc. HNO₃ + conc. H₂SO₄
323 to 333 K
NitrobenzeneC₆H₅NO₂Nitro compound - Step 2
Sn + conc. HCl
AnilineC₆H₅NH₂Amine - Step 3
NaNO₂ + HCl
273 to 278 K
Benzene diazonium chlorideC₆H₅N₂⁺Cl⁻Diazonium salt - Step 4
KI
IodobenzeneC₆H₅IHaloarene
Exam answer
- Step 1: Benzene to nitrobenzene: conc. HNO₃ + conc. H₂SO₄, 323 to 333 K.
- Step 2: Nitrobenzene to aniline: Sn + conc. HCl.
- Step 3: Aniline to benzene diazonium chloride: NaNO₂ + HCl, 273 to 278 K.
- Step 4: Benzene diazonium chloride to iodobenzene: KI.
Reagent and reason, step by step
- Step 1: Benzene to nitrobenzene: conc. HNO₃ + conc. H₂SO₄, 323 to 333 K Nitration: the nitronium ion is the electrophile; keep below 333 K to avoid dinitration.
- Step 2: Nitrobenzene to aniline: Sn + conc. HCl Metal in acid reduces the nitro group; the amine comes out as its salt, so add NaOH at the end.
- Step 3: Aniline to benzene diazonium chloride: NaNO₂ + HCl, 273 to 278 K Diazotisation: keep at 273 to 278 K or the salt decomposes. The acid generates HNO₂ in situ.
- Step 4: Benzene diazonium chloride to iodobenzene: KI Iodide needs no copper catalyst.
Benzene to iodobenzene: quick answers
How many steps does it take to convert benzene to iodobenzene?
4 steps: Benzene, then nitrobenzene, then aniline, then benzene diazonium chloride, then iodobenzene.
Which named reaction is used to convert benzene to iodobenzene?
Diazotisation. A primary aromatic amine reacts with nitrous acid (NaNO2 and HCl) at 273 to 278 K to give a diazonium salt.
What is the reagent for step 1 of benzene to iodobenzene?
Benzene to nitrobenzene: conc. HNO₃ + conc. H₂SO₄, 323 to 333 K. Nitration: the nitronium ion is the electrophile; keep below 333 K to avoid dinitration.