Benzene to N,N-dimethylaniline
4 steps: substitution, then reduction, then substitution, then substitution
BenzeneC₆H₆Arene - Step 1
conc. HNO₃ + conc. H₂SO₄
323 to 333 K
NitrobenzeneC₆H₅NO₂Nitro compound - Step 2
Sn + conc. HCl
AnilineC₆H₅NH₂Amine - Step 3
CH₃I
N-MethylanilineC₆H₅NHCH₃Amine - Step 4
CH₃I
N,N-DimethylanilineC₆H₅N(CH₃)₂Amine
Exam answer
- Step 1: Benzene to nitrobenzene: conc. HNO₃ + conc. H₂SO₄, 323 to 333 K.
- Step 2: Nitrobenzene to aniline: Sn + conc. HCl.
- Step 3: Aniline to N-methylaniline: CH₃I.
- Step 4: N-methylaniline to N,N-dimethylaniline: CH₃I.
Reagent and reason, step by step
- Step 1: Benzene to nitrobenzene: conc. HNO₃ + conc. H₂SO₄, 323 to 333 K Nitration: the nitronium ion is the electrophile; keep below 333 K to avoid dinitration.
- Step 2: Nitrobenzene to aniline: Sn + conc. HCl Metal in acid reduces the nitro group; the amine comes out as its salt, so add NaOH at the end.
- Step 3: Aniline to N-methylaniline: CH₃I Alkylation of an amine with an alkyl halide; NCERT shows it for amines in general.
- Step 4: N-Methylaniline to N,N-dimethylaniline: CH₃I Alkylation of an amine with an alkyl halide; NCERT shows it for amines in general.
Benzene to N,N-dimethylaniline: quick answers
How many steps does it take to convert benzene to N,N-dimethylaniline?
4 steps: Benzene, then nitrobenzene, then aniline, then N-methylaniline, then N,N-dimethylaniline.
Which named reaction is used to convert benzene to N,N-dimethylaniline?
None of the steps has a name. They are substitution and reduction and substitution and substitution, so write the reagent and the condition for each step.
What is the reagent for step 1 of benzene to N,N-dimethylaniline?
Benzene to nitrobenzene: conc. HNO₃ + conc. H₂SO₄, 323 to 333 K. Nitration: the nitronium ion is the electrophile; keep below 333 K to avoid dinitration.