S in H₂SO₄
S is +6 in sulphuric acid.
Oxidation number
Type a formula or an ion: K2Cr2O7, Cr2O7 2-, MnO4-, NH4+ or K4[Fe(CN)6]. Put a known ion in brackets when two elements are unknown. Pick an element to solve for it.
+1H2+6S−2O4
S+6
- Hydrogen is +1 when bonded to non-metals.
- Oxygen is −2 in most compounds.
- The oxidation numbers add up to the charge, 0: 2(+1) + 4(−2) + x = 0.
- x = +6.
How to find it
- Hydrogen is +1 when bonded to non-metals.
- Oxygen is −2 in most compounds.
- The oxidation numbers add up to the charge, 0: 2(+1) + 4(−2) + x = 0.
- x = +6.
All the oxidation numbers in H₂SO₄
- H +12 atoms, hydrogen
- O −24 atoms, oxygen
- S +61 atom, sum rule
S in H₂SO₄: quick answers
What is the oxidation number of S in H₂SO₄?
S in H₂SO₄ (sulphuric acid) is +6.
How do you find the oxidation number of S in H₂SO₄?
Hydrogen is +1 when bonded to non-metals. Oxygen is −2 in most compounds. The oxidation numbers add up to the charge, 0: 2(+1) + 4(−2) + x = 0. x = +6.
What are the oxidation numbers of the other atoms in H₂SO₄?
H +1, O −2. Together with S at +6 they add up to the charge of the compound, 0.