Chromium (Cr)
[Ar] 3d⁵ 4s¹, an exception. 6 unpaired electrons, period 4, group 6, d block.
Element or ion
Type a symbol, a name or an atomic number, add a charge such as Fe3+ or Cl-, or tap an element in the table. Orbitals fill from m = −l up, spin +½ first.
CrChromium, Z = 24, 51.996 u
[Ar] 3d5 4s1
In full: 1s² 2s² 2p⁶ 3s² 3p⁶ 3d⁵ 4s¹
- Blockd block
- Period4
- Group6
- Valence6
- Unpaired6
- MagneticPara
Last electron 3d
- n3shell
- l2d subshell
- m+2orbital
- s+½spin up
Why Cr is an exception
Plain filling would give [Ar] 3d⁴ 4s². A half-filled d subshell (d⁵) is extra stable: five electrons with parallel spins in five orbitals give the largest exchange energy and a symmetrical charge cloud. So one s electron moves into d.
Step by step
- Chromium has 24 electrons.
- Fill in (n + l) order: 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d⁴.
- That gives [Ar] 3d⁴ 4s², but the accepted configuration is [Ar] 3d⁵ 4s¹. A half-filled d subshell (d⁵) is extra stable: five electrons with parallel spins in five orbitals give the largest exchange energy and a symmetrical charge cloud. So one s electron moves into d.
- Write the subshells in order of n: 1s² 2s² 2p⁶ 3s² 3p⁶ 3d⁵ 4s¹.
- Replace the argon core with [Ar]: [Ar] 3d⁵ 4s¹.
Chromium (Cr): the numbers
| Atomic number | 24 |
|---|---|
| Atomic mass | 51.996 u |
| Period | 4 |
| Group | 6 |
| Block | d block |
| Valence electrons | 6 |
| Unpaired electrons | 6 |
| Magnetic | paramagnetic |
| Last electron | 3d: n = 3, l = 2, m = +2, s = +1/2 |
Chromium (Cr): quick answers
What is the electronic configuration of chromium?
Chromium has 24 electrons: 1s² 2s² 2p⁶ 3s² 3p⁶ 3d⁵ 4s¹, or [Ar] 3d⁵ 4s¹ in short.
Why is chromium [Ar] 3d⁵ 4s¹ and not [Ar] 3d⁴ 4s²?
A half-filled d subshell (d⁵) is extra stable: five electrons with parallel spins in five orbitals give the largest exchange energy and a symmetrical charge cloud. So one s electron moves into d.
What are the quantum numbers of the last electron of chromium?
The last electron goes into 3d: n = 3, l = 2, m = +2, s = +1/2. Orbitals fill from m = −l up, spin +½ first.