Vanadium (V)
[Ar] 3d³ 4s². 3 unpaired electrons, period 4, group 5, d block.
Element or ion
Type a symbol, a name or an atomic number, add a charge such as Fe3+ or Cl-, or tap an element in the table. Orbitals fill from m = −l up, spin +½ first.
VVanadium, Z = 23, 50.942 u
[Ar] 3d3 4s2
In full: 1s² 2s² 2p⁶ 3s² 3p⁶ 3d³ 4s²
- Blockd block
- Period4
- Group5
- Valence5
- Unpaired3
- MagneticPara
Last electron 3d
- n3shell
- l2d subshell
- m0orbital
- s+½spin up
Step by step
- Vanadium has 23 electrons.
- Fill in (n + l) order: 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d³.
- Write the subshells in order of n: 1s² 2s² 2p⁶ 3s² 3p⁶ 3d³ 4s².
- Replace the argon core with [Ar]: [Ar] 3d³ 4s².
Vanadium (V): the numbers
| Atomic number | 23 |
|---|---|
| Atomic mass | 50.942 u |
| Period | 4 |
| Group | 5 |
| Block | d block |
| Valence electrons | 5 |
| Unpaired electrons | 3 |
| Magnetic | paramagnetic |
| Last electron | 3d: n = 3, l = 2, m = 0, s = +1/2 |
Vanadium (V): quick answers
What is the electronic configuration of vanadium?
Vanadium has 23 electrons: 1s² 2s² 2p⁶ 3s² 3p⁶ 3d³ 4s², or [Ar] 3d³ 4s² in short.
How many unpaired electrons does vanadium have?
Vanadium has 3 unpaired electrons, so it is paramagnetic. Put one electron in each box of a subshell before pairing (Hund’s rule) to see them.
What are the quantum numbers of the last electron of vanadium?
The last electron goes into 3d: n = 3, l = 2, m = 0, s = +1/2. Orbitals fill from m = −l up, spin +½ first.