Numford
Electronic configuration

Lead (Pb)

[Xe] 4f¹⁴ 5d¹⁰ 6s² 6p². 2 unpaired electrons, period 6, group 14, p block.

Element or ion

Type a symbol, a name or an atomic number, add a charge such as Fe3+ or Cl-, or tap an element in the table. Orbitals fill from m = −l up, spin +½ first.

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H1He2Li3Be4B5C6N7O8F9Ne10Na11Mg12Al13Si14P15S16Cl17Ar18K19Ca20Sc21Ti22V23Cr24Mn25Fe26Co27Ni28Cu29Zn30Ga31Ge32As33Se34Br35Kr36Rb37Sr38Y39Zr40Nb41Mo42Tc43Ru44Rh45Pd46Ag47Cd48In49Sn50Sb51Te52I53Xe54Cs55Ba56Hf72Ta73W74Re75Os76Ir77Pt78Au79Hg80Tl81Pb82Bi83Po84At85Rn86

PbLead, Z = 82, 207.2 u

[Xe] 4f14 5d10 6s2 6p2

In full: 1s² 2s² 2p⁶ 3s² 3p⁶ 3d¹⁰ 4s² 4p⁶ 4d¹⁰ 4f¹⁴ 5s² 5p⁶ 5d¹⁰ 6s² 6p²

[Xe]4f5d6s6p
  • Blockp block
  • Period6
  • Group14
  • Valence4
  • Unpaired2
  • MagneticPara

Last electron 6p

  • n6shell
  • l1p subshell
  • m0orbital
  • s+½spin up
Working

Step by step

  1. Lead has 82 electrons.
  2. Fill in (n + l) order: 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ 5s² 4d¹⁰ 5p⁶ 6s² 4f¹⁴ 5d¹⁰ 6p².
  3. Write the subshells in order of n: 1s² 2s² 2p⁶ 3s² 3p⁶ 3d¹⁰ 4s² 4p⁶ 4d¹⁰ 4f¹⁴ 5s² 5p⁶ 5d¹⁰ 6s² 6p².
  4. Replace the xenon core with [Xe]: [Xe] 4f¹⁴ 5d¹⁰ 6s² 6p².
At a glance

Lead (Pb): the numbers

Atomic number82
Atomic mass207.2 u
Period6
Group14
Blockp block
Valence electrons4
Unpaired electrons2
Magneticparamagnetic
Last electron6p: n = 6, l = 1, m = 0, s = +1/2
Questions

Lead (Pb): quick answers

What is the electronic configuration of lead?

Lead has 82 electrons: 1s² 2s² 2p⁶ 3s² 3p⁶ 3d¹⁰ 4s² 4p⁶ 4d¹⁰ 4f¹⁴ 5s² 5p⁶ 5d¹⁰ 6s² 6p², or [Xe] 4f¹⁴ 5d¹⁰ 6s² 6p² in short.

How many unpaired electrons does lead have?

Lead has 2 unpaired electrons, so it is paramagnetic. Put one electron in each box of a subshell before pairing (Hund’s rule) to see them.

What are the quantum numbers of the last electron of lead?

The last electron goes into 6p: n = 6, l = 1, m = 0, s = +1/2. Orbitals fill from m = −l up, spin +½ first.

Try any element or ion