Ni²⁺ ion
[Ar] 3d⁸. 2 unpaired electrons, paramagnetic.
Element or ion
Type a symbol, a name or an atomic number, add a charge such as Fe3+ or Cl-, or tap an element in the table. Orbitals fill from m = −l up, spin +½ first.
Ni2+Nickel ion, 26 electrons
[Ar] 3d8
In full: 1s² 2s² 2p⁶ 3s² 3p⁶ 3d⁸. Ni loses 4s²
Ni loses 4s²
- Blockd block
- Period4
- Group10
- Outer shell16
- Unpaired2
- MagneticPara
Last electron 3d
- n3shell
- l2d subshell
- m0orbital
- s−½spin down
Step by step
- Nickel has 28 electrons: [Ar] 3d⁸ 4s².
- The ion has 2 fewer, 26 electrons. Remove them from the highest n first.
- Ni loses 4s².
- Ni²⁺ ion: [Ar] 3d⁸, in full 1s² 2s² 2p⁶ 3s² 3p⁶ 3d⁸.
Ni²⁺ ion: the numbers
| Atomic number | 28 |
|---|---|
| Electrons | 26 |
| Period | 4 |
| Group | 10 |
| Block | d block |
| Electrons in the outer shell | 16 |
| Unpaired electrons | 2 |
| Magnetic | paramagnetic |
| Last electron | 3d: n = 3, l = 2, m = 0, s = −1/2 |
Ni²⁺ ion: quick answers
What is the electronic configuration of Ni²⁺?
Ni²⁺ has 26 electrons: 1s² 2s² 2p⁶ 3s² 3p⁶ 3d⁸, or [Ar] 3d⁸. Ni loses 4s².
How many unpaired electrons are there in Ni²⁺?
Ni²⁺ has 2 unpaired electrons, so it is paramagnetic.
Why does Ni lose its outer electrons first?
Electrons leave from the highest n first. The 4s level fills before 3d, but once 3d holds electrons the 4s electrons are the outermost, so they are lost first.